Bit Patterns
What is this?
Sometimes what matters is not the value of a number but the shape made by its on and off switches โ like reading a barcode rather than a price tag. These problems look for arrangements such as switches that strictly alternate on-off-on-off, or treat the whole row of switches as a compact map of which seats in a cinema are taken.
๐ก Fun fact: Gray code, where each step flips just one switch, was patented by Bell Labs physicist Frank Gray in 1953 and is still used on rotary encoders so a sensor never misreads a value while spinning between positions.
๐ The 4 problems in this chapter are free. Sign in with Google or Microsoft to start solving.
Core idea: many problems are really about the shape of the bits, not their value. Shifting a number against itself and XOR-ing exposes where adjacent bits agree or differ, and treating a bitmask as a compact set lets you track occupancy or build sequences with one integer.
The pattern
The central move is shift-then-XOR. If you slide n right by one and XOR with itself, every position where two neighboring bits differ becomes a 1. For alternating bits, that result is all ones, which you confirm by checking (x & (x+1)) == 0. Gray code uses the same neighbor relationship the other way: i ^ (i >> 1) maps consecutive integers to codes that differ by exactly one bit, generating the whole sequence directly.
Reversing bits flips the layout end to end โ either swap symmetric positions one pair at a time, or use a divide-and-conquer cascade of masks that swaps halves, then quarters, then bytes in O(log w) steps. The seat-allocation problem treats a row as a bitmask of occupied seats: set a bit per booked seat, then AND against fixed window masks to test whether a contiguous block of seats is still free, updating the mask as families are placed.
The problems
- Binary Number with Alternating Bits โ shift-XOR to mark differing neighbors, then check the result is all ones.
- Gray Code โ generate the reflected sequence directly with
i ^ (i >> 1). - Reverse Bits โ swap symmetric bits, or cascade divide-and-conquer masks for
O(log w)reversal. - Cinema Seat Allocation โ keep a per-row bitmask of occupied seats and AND against window masks to find free contiguous blocks.
Key takeaways
- Shift-then-XOR reveals where adjacent bits differ โ the basis of the alternating-bits check.
i ^ (i >> 1)turns a counter into Gray code, where successive values differ by one bit.- Reverse bits by symmetric swaps or a log-step mask cascade rather than rebuilding the number digit by digit.
- A bitmask doubles as a compact set: one integer can track an entire row's occupancy.
- Precomputed window masks make "is this block free?" a single AND, turning layout questions into bit tests.
Core idea: Reversing bits is just mirroring them around the center โ do it one bit at a time, or fold the word in half, then in quarters, then eighths, until every bit has crossed to its mirror seat.
Problem, rephrased
You're handed a fixed-width 32-bit unsigned integer. Picture its bits laid out left-to-right, position 31 down to position 0. Your job: produce a new 32-bit value where the bit at position 0 lands at position 31, position 1 at position 30, and so on โ a perfect end-for-end mirror.
It's the bit-level equivalent of reversing a string, except the "string" is always exactly 32 characters of 0/1 and you must keep it that width.
| Input (decimal) | Input (32-bit binary) | Output (32-bit binary) | Output (decimal) |
|---|---|---|---|
43261596 |
00000010100101000001111010011100 |
00111001011110000010100101000000 |
964176192 |
1 |
00000000000000000000000000000001 |
10000000000000000000000000000000 |
2147483648 |
4294967295 |
11111111111111111111111111111111 |
11111111111111111111111111111111 |
4294967295 |
Notice the all-ones case is its own reverse โ a palindrome. Most inputs are not.
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