Structure and Measure
What is this?
Sometimes you don't want to change a tree, you just want to understand its shape. Is it neatly filled in, level by level, like seats packed into a theatre row? How few steps to the nearest exit? Where do two people's family lines first meet? These problems are about reading those facts off a tree, and the trick is picking the right way to walk it โ sweeping across levels for layout questions, or going deep so each node can hear back from its children.
๐ก Fun fact: A "complete" binary tree โ one filled level by level with no gaps โ is the secret backbone of the heap, the data structure that powers priority queues. That tidy gap-free shape lets the whole tree be stored in a plain flat array with no pointers at all.
๐ The 3 problems in this chapter are free. Sign in with Google or Microsoft to start solving.
Core idea: Before you can transform a tree, you have to read it. This bucket is about extracting facts from a binary tree's shape: is it filled in level by level, how shallow is its nearest leaf, and where do two nodes' paths first join. Two tools cover all three โ a level-order BFS that walks the tree row by row, and a post-order DFS that lets each node decide based on what its two children reported back.
The pattern
A binary tree carries two kinds of information: its layout (how nodes are arranged across levels) and its relationships (how nodes sit relative to one another on root-to-leaf paths). BFS is the natural lens for layout questions because it visits nodes in the exact order a "complete" tree would fill them. DFS โ specifically post-order โ is the lens for relationship questions, because a node can only judge itself once both children have answered.
The skill is matching the question to the traversal. "Is every level packed, left to right?" is a BFS gap-detection problem. "How few steps to the closest leaf?" is shortest-path, so BFS again. "Where do these two nodes meet?" is about subtree membership, so DFS.
The problems
- Check Completeness of a Binary Tree โ BFS the tree and watch for the first missing child; once you've seen a gap, every node after it must also be a leaf-level gap, or the tree isn't complete.
- Minimum Depth of Binary Tree โ the shallowest leaf. BFS finds it the instant it dequeues the first leaf (no need to scan the whole tree); a DFS works too but must be careful that a missing child is not a leaf.
- Lowest Common Ancestor of a Binary Tree โ post-order DFS returns whether each subtree contains a target; the node where the two targets surface from different children is the split point and the answer.
Key takeaways
- Match the traversal to the question: BFS for level/layout and shortest-distance facts, post-order DFS for relationships between nodes.
- BFS can stop early โ minimum depth is found at the first leaf dequeued, not after a full sweep.
- A "gap" flag turns completeness into a single pass โ once a hole appears, no later node may have children.
- Why interviewers like it: these problems reveal whether you reach for the right traversal on instinct rather than forcing one tool onto every shape.
Order: Minimum Depth โ Check Completeness โ Lowest Common Ancestor.
Check Completeness of a Binary Tree
Core idea: A complete tree fills like water poured in row by row, left to right โ so once you hit the first empty slot, everything after it must be empty too.
Problem, rephrased
Imagine you run a stadium and you seat fans row by row, strictly left to right. Row 1 (one seat) must be full before anyone sits in row 2 (two seats), which must be full before row 3 (four seats), and so on. The only row allowed to be partially filled is the last one being seated โ and even there, seats must fill left-to-right with no gaps in between.
You're handed a seating chart shaped as a binary tree (root = the front seat, each seat has up to two seats behind-left and behind-right). Your job: report whether the fans were seated by the rules โ return True if the tree is complete, False otherwise.
A tree is complete when every level is fully filled except possibly the last, and the last level's nodes are pushed as far left as possible.
| Input (tree, level-order) | Output | Why |
|---|---|---|
[1,2,3,4,5,6] |
True |
Every level full except last; last fills left-to-right |
[1,2,3,4,5,null,7] |
False |
Slot 6 (3's left child) is empty, but slot 7 (3's right child) is filled |
[1,2,3,4,null,6] |
False |
Slot 5 (2's right child) is empty, then slot 6 reappears โ a gap in the middle |
[1] |
True |
Single node |
[] |
True |
Empty tree is vacuously complete |
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